Question

As the result of experimental work, a student finds the density of a liquid to be 0.1369 g/mL. The known density of that liquid is 0.1478 g/mL. What is the percent error of this student's work [% error = (actual - experimental)/actual. Then multiply by 100]. Sig figs apply.

a 0.07374%
b 7.37%
c 7.375%
d 7.4%

Answer 1

The answer is option C

Step-by-step explanation:

The percentage error of a certain measurement can be found by using the formula

`P(\%) = (error)/(actual \: \: number) * 100\% \\`

From the question

actual density = 0.1478 g/mL

error = 0.1478 - 0.1369 = 0.0109

The percentage error is

`P (\%) = (0.0109)/(0.1478) * 100 \\ = 7.37483085...`

We have the final answer as

7.375 %

Hope this helps you