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2 votes
2 votes
Hi guys please help meee

Last question but im having trouble answering it
Please dont just guess I really need this!!!

Hi guys please help meee Last question but im having trouble answering it Please dont-example-1
User Owenn
by
2.6k points

2 Answers

10 votes
10 votes

Answer:

B. 10

Step-by-step explanation:

2 1/8 * 2 2/3

= 8 * 2 + 1 = 17

2 1/8 = 17/8

= 3 * 2 + 2 = 8

2 2/3 = 8/3

17/8 * 8/3

17 * 8 = 136

3 * 8 = 24

136/24 = 17/3 = 5 2/3

5 + 2 + 3 = 10

so I think B. 10 is the answer

User PramodValavala
by
2.7k points
12 votes
12 votes

Answer: 10

=======================================================

Step-by-step explanation:

We'll start off converting each mixed number into an improper fraction.

The formula to use is
A (b)/(c) = (A*c+b)/(c)

So,


A (b)/(c) = (A*c+b)/(c)\\\\2 (1)/(8) = (2*8+1)/(8)\\\\2 (1)/(8) = (16+1)/(8)\\\\2 (1)/(8) = (17)/(8)\\\\

And,


A (b)/(c) = (A*c+b)/(c)\\\\2 (2)/(3) = (2*3+2)/(3)\\\\2 (2)/(3) = (6+2)/(3)\\\\2 (2)/(3) = (8)/(3)\\\\

So the task of computing
2 (1)/(8) * 2 (2)/(3) is exactly the same as computing
(17)/(8) * (8)/(3)

Notice how we have an 8 up top and an 8 down below. Those 8's cancel out and we're left with
(17)/(3). That fraction does not reduce any further.

The last step is to convert that improper fraction result to a mixed number.


(17)/(3) = (15+2)/(3)\\\\(17)/(3) = (15)/(3)+(2)/(3)\\\\(17)/(3) = 5+(2)/(3)\\\\(17)/(3) = 5 (2)/(3)\\\\

Or you could note that 17/3 leads to 5 remainder 2. The 5 is the whole part and the 2 forms the numerator of the fractional part 2/3.

The value is in
A (b)/(c) form where

  • A = 5
  • b = 2
  • c = 3

Therefore, A+b+c = 5+2+3 = 10

User Therkel
by
3.2k points