Given:
Sum of two consecutive integers is 325.
To find:
The number that is the least of the two consecutive integers.
Solution:
Let the two consecutive integers are x and x+1. So,
![x+(x+1)=325](https://img.qammunity.org/2021/formulas/mathematics/high-school/m6r89cqkpzbgd2yftvslmquq2sfadsxb7r.png)
![2x+1=325](https://img.qammunity.org/2021/formulas/mathematics/high-school/jixbfmt3jiamdf22zwoqtih2wbj94ykm32.png)
Subtract 1 from both sides.
![2x=324](https://img.qammunity.org/2021/formulas/mathematics/high-school/7lxhbd6euk6evnbui5njgxh33hbtu05tbq.png)
Divide both sides by 2.
![x=(324)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/8tqbfh8hk15bdjxyxusr2scefqy1oj6u7o.png)
![x=162](https://img.qammunity.org/2021/formulas/mathematics/high-school/sldci2fv0jzrbv92n61vrymliyuk3khll0.png)
The second integer is
![x+1=162+1=163](https://img.qammunity.org/2021/formulas/mathematics/high-school/hpz1vlnn22i4y4g3mxt7g8z5v2y6qkdo2k.png)
Since
, therefore, the least of the two consecutive integers is 162.