Question

What is the midpoint of segment EF? E(-8,1) and F(1,1

Answer 1

Explanation:

Hey there!

The given points are; (-8,1) and F (1,1). Let M(x,y) be the midpoints.

Now,

Using midpoint formulae.

`(x,y) = ( (x1 + x2)/(2) , (y1 + y2)/(2) )`

Put all values.

`(x,y) =( ( - 8 + 1)/(2) , (1 + 1)/(2) )`

Simplify it to get answer.

`(x,y) = ( ( - 7)/(2) , (2)/(2))`

`(x,y) = (( - 7)/(2) ,1)`

Therefore the slope is M(-7/2,1).

Hope it helps...

Answer 2

The answer is

`( - (7)/(2) \: , \: 1) \\`

Explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

`M = ( (x1 + x2)/(2) , \: (y1 + y2)/(2) )\\`

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

E(-8,1) and F(1,1)

The midpoint is

`M = ( ( - 8 + 1)/(2) \: , \: (1 + 1)/(2) ) \\ = ( - (7)/(2) \: , \: (2)/(2) )`

We have the final answer as

`( - (7)/(2) \: , \: 1) \\`

Hope this helps you