Question

A 6.0 MeV alpha particle beam of cross section 5 cm2 is completely stopped in an ionization chamber producing a saturation current of 0.08 nA. What is the deBroglie wavelength of the alpha particle? If the energy necessary to create an ion-electron pair is 33 eV/ip, calculate the fluence rate?

Answer 1

`v=6.0MeV\\h=6.626\cdot10^(-34)\\dq=33\\`

Solution

`m_\alpha =6.64\cdot 10^(-27)\\\lambda=(h)/(p)\\p=√(2m\cdot V)\\\lambda=\frac{6.628 \cdot10^(-34)}{\sqrt{2(6.64\cdot10^(-27))(6\cdot10^6)}}\\\\\lambda =2.35\cdot10^(-34)\\Fluence Rate =(d(N))/(d(t)\cdot d(S))=(d(N)\cdot d(q))/(d(q)\cdot d(t)\cdot d(S))=(d(N))/(d(q))\frac{V} {\cdot d(S)}\\\\\=(6\cdot 10^6)/(33) \cdot(0.08\cdot10^(-9))/(4\cdot\pi\cdot25\cdot10^(-4))\\\\=0.000463\\E_p=4.63\cdot10^(-4)\\`

`=(6*10^6\cdot 0.08*10^(-9))/(33\cdot4\pi\cdot 25*10^-4) \\\\E_P=4.63*10^(-4)`

Step-by-step explanation:

First enlist all the variables

then solve using calculator