Answer:
The water required to pump all the water to a platform 2 feet above the top of the pool is is 6061310.32 foot-pound.
Step-by-step explanation:
Given that,
Radius = 21 feet
Height = 10 feet
Weighing = 62.5 pounds/cubic
Work = 4329507.37572
Height = 2 feet
Let's look at a horizontal slice of water at a height of h from bottom of pool
We need to calculate the area of slice
Using formula of area
![A=\pi r^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/y53l5bajukem3vosj2tgna2lxvbu4ngh5h.png)
Put the value into the formula
![A=\pi*21^2](https://img.qammunity.org/2021/formulas/physics/high-school/d1q9gnv8d5vnmw0mva4g4vjprid5ew34gq.png)
![A=441\pi\ feet^2](https://img.qammunity.org/2021/formulas/physics/high-school/roupna7a7f5us4oa6wvkzy1yil4dliydq5.png)
Thickness of slice
![t=\Delta h\ ft](https://img.qammunity.org/2021/formulas/physics/high-school/7xqwiu4731qnsrvosaux76xxad8pxjktsz.png)
The volume is,
![V=(441\pi*\Delta h)\ ft^3](https://img.qammunity.org/2021/formulas/physics/high-school/1zutu6wwg6l411r08fwlc5wt47mwdgt7bm.png)
We need to calculate the force
Using formula of force
![F=W* V](https://img.qammunity.org/2021/formulas/physics/high-school/gt8ki8j6oofhriyaig430ts2g402fo5z0x.png)
Where, W = water weight
V = volume
Put the value into the formula
![F=62.5*(441\pi*\Delta h)](https://img.qammunity.org/2021/formulas/physics/high-school/gi811uux14nsuk402k6r936tg3pevhxrl1.png)
![F=27562.5\pi*\Delta h\ lbs](https://img.qammunity.org/2021/formulas/physics/high-school/sk436ar00mffc7navckmip9dqzslsg3vhf.png)
We need to calculate the work done
Using formula of work done
![W=F* d](https://img.qammunity.org/2021/formulas/physics/middle-school/t8m4y6nwjve3l9pt55zlwkc3lom4i01ach.png)
Put the value into the formula
![W=27562.5\pi*\Delta h*(10-h)\ ft\ lbs](https://img.qammunity.org/2021/formulas/physics/high-school/42arq11dfbjj2df8su622b4b2ezqel4que.png)
We do this by integrating from h = 0 to h = 10
We need to find the total work,
Using formula of work done
![W=\int_(0)^(h){W}](https://img.qammunity.org/2021/formulas/physics/high-school/fu2gagadnvag18fk92783mnjaxdb95rokx.png)
Put the value into the formula
![W=\int_(0)^(10){27562.5\pi\\times(10-h)}dh](https://img.qammunity.org/2021/formulas/physics/high-school/was0u512whlr0cwkubexw6rwx8eruf3dzu.png)
![W=27562.5\pi(10h-(h^2)/(2))_(0)^(10)](https://img.qammunity.org/2021/formulas/physics/high-school/7neb27eh2g5zseu6ffnzpzj5uce7ewr02m.png)
![W=27562.5\pi(10*10-(100)/(2)-0)](https://img.qammunity.org/2021/formulas/physics/high-school/v5lbtnjj49npyycgg87e8857te7oshoc10.png)
![W=4329507.37572](https://img.qammunity.org/2021/formulas/physics/high-school/8bijjwiwc4xq6hmmo0bv89qpy7i4a55122.png)
To pump 2 feet above platform, then each slice has to be lifted an extra 2 feet,
So, the total distance to lift slice is (12-h) instead of of 10-h
We need to calculate the water required to pump all the water to a platform 2 feet above the top of the pool
Using formula of work done
![W=\int_(0)^(h){W}](https://img.qammunity.org/2021/formulas/physics/high-school/fu2gagadnvag18fk92783mnjaxdb95rokx.png)
Put the value into the formula
![W=\int_(0)^(10){27562.5\pi\\times(12-h)}dh](https://img.qammunity.org/2021/formulas/physics/high-school/r5ooz93br8kfu5ry1wmsifm6dqata8jsoz.png)
![W=27562.5\pi(12h-(h^2)/(2))_(0)^(10)](https://img.qammunity.org/2021/formulas/physics/high-school/2hz5gypjeuit6h8nwqx6oobvnytqt5d2z1.png)
![W=27562.5\pi(12*10-(100)/(2)-0)](https://img.qammunity.org/2021/formulas/physics/high-school/x07dy9pj6a7v5s94nltzaoitm2dt2dt656.png)
![W=1929375\pi](https://img.qammunity.org/2021/formulas/physics/high-school/ofmf0s03gwbjbiq89hk6s8ofbx6q1ssqfq.png)
![W=6061310.32\ foot- pound](https://img.qammunity.org/2021/formulas/physics/high-school/pgkftm5inmym0v3hbe2gj2awgg0tdbup2t.png)
Hence, The water required to pump all the water to a platform 2 feet above the top of the pool is is 6061310.32 foot-pound.