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Circle O is shown. Secants C A and C E intersect at point C outside of the circle to form an angle with measure 36 degrees. Secant C A intersects the circle at point B, and secant C E intersects the circle at point D. Arc B D is 48 degrees. In circle O, what is mArc A E?

User Blazerix
by
4.1k points

2 Answers

7 votes

Answer:

its C, 120

Explanation:

got it right on the test

User Btevfik
by
4.2k points
2 votes

Answer:

120°

Explanation:

The external angle <C outside the circle can be expressed in terms of length of arc AE and BD using the formula below.

<C =
(AE-BD)/(2) \\

Next is to make the length of arc AE the subject of the formula;

<C =
(AE-BD)/(2) \\

cross multiply


2<C = AE-BD

add BD to both sides of the equation


2<C+BD = AE-BD+BD\\2<C +BD = AE


AE = 2<C +BD

Given

<C = 36°

arc BD = 48°

Substitute the given parameters into the formula;


AE = 2<C +BD\\AE = 2(36)+48\\AE = 72+48\\AE = 120^0\\

Hence mArc is 120°

User Jski
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4.2k points