Question

As the earth rotates through one revolution, a person standing on the equator traces out a circular path whose radius is equal to the radius of the earth (6.38×10^6). What is the average speed of this person in meters per second? If we are standing in latitude 43° north what is our average speed?

Answer 1

The average speed will be "1038 mph".

Step-by-step explanation:

Period for one revolution is:

T = 24 hours

= 86,400 sec

x = c = 2πr

The given values is:

r = 6.38×10⁶ m

Now,

⇒
`T=(2 \pi r)/(v)`

Or,

⇒
`v=(2 \pi r)/(T)`

On substituting the values, we get

`=(2 \pi (6.38* 10^6))/(86,400)`

`=464 \ min/sec`

`=(464 (min)/(sec)) ((3600 \ sec)/(1 \ hour) )((1 \ mi)/(1609 \ m) )`

`=1038 \ mph`