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Consider the paraboloid z=x2+y2. The plane 8x−5y+z−2=0 cuts the paraboloid, its intersection being a curve. Find "the natural" parametrization of this curve. Hint: The curve which is cut lies above a circle in the xy-plane which you should parametrize as a function of the variable t so that the circle is traversed counterclockwise exactly once as t goes from 0 to 2*pi, and the parameterization starts at the point on the circle with largest x coordinate. Using that as your starting point, give the parametrization of the curve on the surface.

c(t)=(x(t),y(t),z(t)), wherex(t)=y(t)=z(t)=

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Answer:

The parametrization of the curve on the surface is


c(t) = [x(t) , y(t), z(t)] \equiv [(√(97) )/(2) cost - 4 , (√(97) )/(2) sint + (5)/(2) , 5(√(97) )/(2) sint -8 (√(97) )/(2) cost +(93)/(2) ]

Where


x =  (√(97) )/(2) cost - 4


y = (√(97) )/(2)  sint  + (5)/(2)


z = 5(√(97) )/(2) sint -8 (√(97) )/(2) cost +(93)/(2)

Explanation:

From the question we are told that

The equation for the paraboloid is
z = x^2 + y^2

The equation of the plane is
8x - 5y + z -2 = 0

Form the equation of the plane we have that


z = 5y -8x +2

So


x^2 + y^2 = 5y -8x +2

=>
x^2 + 8x + y^2 -5y = 2

Using completing the square method to evaluate the quadratic equation we have


(x + 4)^2 + (y - (5)/(2) )^2 = 2 +((5)/(2) )^2 + 4^2


(x + 4)^2 + (y - (5)/(2) )^2 = (97)/(4)


(x + 4)^2 + (y - (5)/(2) )^2 = ( (√(97) )/(2) )^2

representing the above equation in parametric form


(x + 4) = (√(97) )/(2) cost ,
(y -(5)/(2) ) = (√(97) )/(2) sin t


x = (√(97) )/(2) cost - 4


y = (√(97) )/(2) sint + (5)/(2)

So from
z = 5y -8x +2


z = 5[(√(97) )/(2) sint + (5)/(2)] -8[ (√(97) )/(2) cost - 4] +2


z = 5(√(97) )/(2) sint + (25)/(2) -8 (√(97) )/(2) cost + 32 +2


z = 5(√(97) )/(2) sint -8 (√(97) )/(2) cost +(93)/(2)

Generally the parametrization of the curve on the surface is mathematically represented as


c(t) = [x(t) , y(t), z(t)] \equiv [(√(97) )/(2) cost - 4 , (√(97) )/(2) sint + (5)/(2) , 5(√(97) )/(2) sint -8 (√(97) )/(2) cost +(93)/(2) ]

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