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If tan(theta)=3/5 and sin(theta) is in quadrant 1, then sin(theta)= 1 + (1)/( (3)/(4) ) = (1)/( \sin(theta ) ) is this the right equation and if so how do you solve it​
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If tan(theta)=3/5 and sin(theta) is in quadrant 1, then sin(theta)=


1 + (1)/( (3)/(4) ) = (1)/( \sin(theta ) )
is this the right equation and if so how do you solve it​

User Andreas Hunter
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5.3k points

1 Answer

4 votes

Answer:

Explanation:

If tan(theta)=3/5 and sin(theta) is in quadrant 1, then sin(theta)= 1 + (1)/( (3)/(4) ) = (1)/( \sin-example-1
User Efi Fogel
by
5.8k points
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