Question

A ship with an initial speed of 6.23 m/s approaches a dock that is 255 m

away. If the ship accelerates uniformly and comes to rest in 82 s, what is
its acceleration?

Answer 1

a = 0.0761 [m/s^2]

Step-by-step explanation:

This problem can be solved using kinematics equations, and by means of the following equation:

`x=x_(0) +v_(0)*t-((1)/(2) ) *a*t^(2)`

where:

Xo = initial location = 0

x = final location = 255 [m]

Vo = initial velocity = 6.23 [m/s]

t = time = 82 [s]

a = aceleration [m/s^2]

Since the ship slows down to rest, the last expression of the equation will be taken with a negative sign

255 = 0 + (6.23*82) - (0.5*a*82^2)

255 - (6.23*82) = - 3362*a

a = 0.0761 [m/s^2]