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3. Find the equation of a line perpendicular to y=-9x+b and through point (-18,3)​

1 Answer

4 votes

Answer:

y =
(1)/(9) x + 1

Explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

y = - 9x + b ← is in slope- intercept form

with slope m = - 9

Given a line with slope m then the slope of a line perpendicular to it is


m_(perpendicular) = -
(1)/(m) = -
(1)/(-9) =
(1)/(9) , thus

y =
(1)/(9) x + b ← is the partial equation

To find b substitute (- 18, 3) into the partial equation

3 = 2 + b ⇒ b = 3 - 2 = 1

y =
(1)/(9) x + 1 ← equation of perpendicular line

User Rhlobo
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