Question

I really need help with this problem.

A mixture contains 21.7g NaCl, 3.74g KCl, and 9.76g LiCl.
How many moles of NaCl are in this mixture?
The molar mass is provided in picture attached.

Answer 1

.371 mole of NaCl

Step-by-step explanation:

Na Cl Mole weight = 22.989 + 35.45 = 58.439 g/mole

21.7 g / 58.439 g/mole = .371 mole