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What volume is occupied by 2.1 g O2 at 13 C and a pressure of 0.1atm?
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What volume is occupied by 2.1 g O2 at 13 C and a pressure of 0.1atm?

User Yarun Can
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1 Answer

1 vote

PV=nRT

n = mole = 2.1 g : 32 g/mole = 0.065

T = 13 + 273 = 286 K

V = nRT/P

V = (0.065 x 0.08205 x 286)/0.1

V = 15.253 L

User Whallz
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