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Write an equation in slope-intercept form of the line that bisects the angle formed by BA and BC

Write an equation in slope-intercept form of the line that bisects the angle formed-example-1

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Given:

Angled formed by ray BA and ray BC is 90 degrees.

To find:

The equation of line that bisects the angle formed by ray BA and ray BC.

Solution:

If a line bisects the angle formed by ray BA and ray BC, then it must be passes through point B and makes angles of 45 degrees with ray BA and ray BC.

It is possible if the line passes though point B(-1,3) and other point (-2,4).

Equation of line is


y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)


y-3=(4-3)/(-2-(-1))(x-(-1))


y-3=(1)/(-1)(x+1)


y-3=-x-1

Add 3 on both sides.


y=-x-1+3


y=-x+2

Therefore, the required equation of line is
y=-x+2.

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