Given:
Angled formed by ray BA and ray BC is 90 degrees.
To find:
The equation of line that bisects the angle formed by ray BA and ray BC.
Solution:
If a line bisects the angle formed by ray BA and ray BC, then it must be passes through point B and makes angles of 45 degrees with ray BA and ray BC.
It is possible if the line passes though point B(-1,3) and other point (-2,4).
Equation of line is
![y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)](https://img.qammunity.org/2021/formulas/mathematics/college/2ft4curll9g1xqqt5yfsd57zfqfj5z775i.png)
![y-3=(4-3)/(-2-(-1))(x-(-1))](https://img.qammunity.org/2021/formulas/mathematics/high-school/lk1ldjavxrflifydo41cmxpa8r6q8dfy7c.png)
![y-3=(1)/(-1)(x+1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/dj7mf3ajg4lchmvotehk1u5nct97z4dkbc.png)
![y-3=-x-1](https://img.qammunity.org/2021/formulas/mathematics/high-school/xkkyzovfo6nf9epd6acvr7wbstuk8khn16.png)
Add 3 on both sides.
![y=-x-1+3](https://img.qammunity.org/2021/formulas/mathematics/high-school/mm6hr7uz3pf0gr1d77sxufuotslidabq51.png)
![y=-x+2](https://img.qammunity.org/2021/formulas/mathematics/high-school/9h485jp0xp640o25bkw1hnnjxteume6avw.png)
Therefore, the required equation of line is
.