Final answer:
The solution set for |s/2 + 4| < 2 is all the values of 's' between -12 and -4, not including the endpoints. This is depicted on a number line as a shaded region between open circles at -12 and -4.
Step-by-step explanation:
We are given the inequality |\frac{s}{2} + 4| < 2. To find the solution set, we first consider the absolute value expression without the inequality, which is split into two equations because absolute value represents the distance from zero: one for when the expression inside is positive (\(\frac{s}{2} + 4 = 2\)) and one for when it is negative (\(\frac{s}{2} + 4 = -2\)).
Solve these two equations:
\(\frac{s}{2} + 4 = 2\) leads to \(\frac{s}{2} = -2\) and then \(s = -4\).
\(\frac{s}{2} + 4 = -2\) leads to \(\frac{s}{2} = -6\) and then \(s = -12\).
The solution set of the inequality is all values of 's' between -12 and -4. On a number line, this is represented with open circles at -12 and -4, with the space between them shaded, as the inequality is strict (<) and does not include the endpoints.
The correct number line is the one going from negative 14 to positive 10 with open circles at negative 12 and negative 4 with everything between the points shaded.