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6 votes
Four circles, each with a radius of 2 inches, are removed from a square.

Four circles, each with a radius of 2 inches, are removed from a square. What is the remaining area of the square?

(16 – 4π) in.2
(16 – π) in.2
(64 – 16π) in.2
(64 – 4π) in.2

User Mohit Gupta
by
2.6k points

1 Answer

27 votes
27 votes

Given:

Given that the radius of the circle is 2 inches.

We need to determine the area of the remaining square.

Area of a square:

Given that each circle has a radius of 2 inches.

Then, the diameter of each circle is 4 inches.

Hence, the side length of the square is 2 × 4 = 8 inches.

The area of the square is given by


A=s^2


A=8^2


A=64
in^2

Thus, the area of the square is 64 square inches.

Area of the four circles:

The area of one circle is given by


A=\pi r^2

Substituting r = 2, we have;


A=4\pi

Thus, the area of one circle is 4π in²

The area of 4 circles is 4 × 4π =16π in²

Hence, the area of the 4 circles is 16π in²

Area of the remaining square:

The area of the remaining square is given by

Area = Area of the square - Area of four circles.

Substituting the values, we get;


Area=64-16\pi

Thus, the area of the remaining square is (64 - 16π) in²

Hence, Option c is the correct answer.

User Mark Sivill
by
3.0k points