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Larry pays $20.69 for 4 cases of soda and 3 bags of chips one case of soda costs $1.55 more than one bag of chips. Let c represent the cost of one bag of chips.type the equation that represents this situation

User Zia Khan
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Given:

Larry pays $20.69 for 4 cases of soda 3 bags of chips.

One case of soda costs $1.55 more than one bag of chips.

To find:

The equation that represents this situation.

Solution:

Let cost of one bag of chips be $c. So,

Cost of One case of soda = $(c+1.55)

Cost of 4 cases of soda 3 bags of chips is


Cost=4(c+1.55)+3(c)

It is given that Larry pays $20.69 for 4 cases of soda 3 bags of chips. So, the cost is $20.69 for 4 cases of soda 3 bags of chips.


4(c+1.55)+3c=20.69

Therefore, the required equation is
4(c+1.55)+3c=20.69.

User Mariely
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