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Find an equation for the perpendicular bisector of the line segment whose endpoints

are (1,3) and (-9,7).
I need help :(

1 Answer

6 votes

Answer: y = (5/2)x + 15

This is the same as y = 2.5x+10 since 5/2 = 2.5

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Step-by-step explanation:

Let's find the slope of the line through those given points

m = (y2-y1)/(x2-x1)

m = (7-3)/(-9-1)

m = 4/(-10)

m = -2/5

To find the perpendicular slope, we flip the fraction and flip the sign

flip the fraction: -2/5 turns into -5/2

flip the sign: -5/2 turns into 5/2

The perpendicular slope is 5/2

Side note: The original slope (-2/5) and the perpendicular slope (5/2) multiply to -1.

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Now find the midpoint

We add the x coordinates of the original points to get 1+(-9) = -8, which cuts in half to -8/2 = -4. This is the x coordinate of the midpoint.

Do the same for the y coordinates. First add: 3+7 = 10, then cut in half: 10/2 = 5. The y coordinate of the midpoint is 5.

The midpoint is (-4,5)

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The perpendicular bisector will go through this midpoint. It has a slope of m = 5/2

Turn to point slope form to find the equation we need

y - y1 = m(x - x1)

y - 5 = (5/2)(x - (-4))

y - 5 = (5/2)(x + 4)

y - 5 = (5/2)x + (5/2)*4

y - 5 = (5/2)x + 10

y = (5/2)x + 10 + 5

y = (5/2)x + 15

y = 2.5x + 15 ... since 5/2 = 2.5

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