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Three consecutive even integers have a sum of -48. Find the largest integer.

1 Answer

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Answer:

- 14

Explanation:

{x - some integer}

2x - the first even integer

2x+2 - the second consecutive even integer

2x+4 - the third consecutive even integer (the largest)

2x + 2x+2 + 2x+4 - the sum of three consecutive even integers

2x + 2x+2 + 2x+4 = -48

6x + 6 = -48

÷3 ÷3

2x + 2 = -16

+2 +2

2x+4 = -14

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