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Point S is on line segment RT. Given RS = 4x – 10, ST = 2x – 10, and

RT = 4x – 4, determine the numerical length of RS.

User Mike Ross
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2 Answers

3 votes

Answer:

RS=4

Explanation:

User Lindy
by
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3 votes

Answer:

The numerical length of RS is 22 units

Explanation:

∵ Point S is on the line segment RT

That means S divide RT into two parts RS and ST

RS + ST = RT

∵ RS = 4x - 10

∵ ST = 2x - 10

∵ RT = 4x - 4

Substitute them in the statement above

4x - 10 + 2x - 10 = 4x - 4

Add the like terms in the left side

∴ (4x + 2x) + (-10 + -10) = 4x - 4

∴ 6x + (-20) = 4x - 4

∴ 6x - 20 = 4x - 4

Add 20 to both sides

∴ 6x -20 + 20 = 4x - 4 + 20

∴ 6x = 4x + 16

Subtract 4x from both sides

∴ 6x - 4x = 4x - 4x + 16

∴ 2x = 16

Divide both sides by 2 to find x


(2x)/(2)=(16)/(2)

x = 8

Substitute the value of x in Rs to find its length

∵ RS = 4(8) - 10

∴ RS = 32 - 10

RS = 22 units

The numerical length of RS is 22 units

User Lekoaf
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