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HELP PLEASE ASAP

A can of tuna, starting from rest, is dropped off a building. If it is only being pulled down by gravity (-
9.8 m/s2) and it hits the ground 3.2s later, how far (Ax) did it drop?

1 Answer

3 votes

Answer: (displacement/delta x) = -50. m, and distance dropped = 50. m (50. m below the starting location)

Step-by-step explanation:

We know that the initial velocity of the tuna can is 0 m/s, as it is at rest. Also, we have the acceleration caused by gravity (-9.8 m/s^2). The time for the trip is 3.2 s. We need to find the displacement, or delta x.

To do this, we need to use a freefall equation. The one we can use with initial velocity, time, and acceleration would be the following:

d = (initial velocity)(time) + (1/2)(acceleration caused by gravity)(time)^2

d = (vi)(t) + 1/2(g)(t)^2

d = (0 m/s)(3.2 s) + 1/2(-9.8 m/s^2)(3.2 s)^2

d = 1/2(-9.8 m/s^2)(3.2 s)^2

d = -4.9(3.2)^2

d = -4.9(10.24)

d = -50.176 = -50. m

User Hardik Masalawala
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