Question

Solve 8cx + 5 – 4cx = 19 for x. Please explain how you did it.

Answer 1

`\tt{Hey~there!`

`\tt{8cx+5-4cx=19`

`\tt{Add~-5~to~both~sides:`

`\tt{4cx+5+-5=19+-5`

`\tt{4cx=14`

`\tt{Divide~both~sides~by~4c:`

`\tt{(4cx)/(4c)=(14)/(4c)`

`\boxed{\tt{x=(7)/(2c)}}`

`\tt{Hope~this~helps!`

`\boxed{\tt{-TestedHyperr}}`

Answer 2

x=7/(2c)

1. Combine like terms and move constants to the right side
4cx=14

2. Divide both sides by 4c to isolate x
x=14/4c= 7/2c