Question

The literature value for the density of aluminum is 2.6 g/mL. If an experimenter

calculates a value of 2.2 g/mL, what is their percent error?

Answer 1

The answer is

15.38%

Step-by-step explanation:

The percentage error of a certain measurement can be found by using the formula

`P(\%) = (error)/(actual \: \: number) * 100\% \\`

From the question

actual density = 2.6 g/mL

error = 2.6 - 2.2 = 0.4

The percentage error is

`P( \% ) = (0.4)/(2.6) * 100 \\ = 15.384615...`

We have the final answer as

15.38%

Hope this helps you