Question

A 75 kg doctor delivers a 4 kg baby and holds it at arm's length (0.3 m). Using the Universal Law of Gravitation formula below, identify F, G, m1, m2, r. *

Answer 1

m₁ = 75 kg

m₂ = 4 kg

r = 0.3 m

G = 6.67 x 10⁻¹¹ Nm²/kg²

F = 2.223 x 10⁻⁷ N

Step-by-step explanation:

Given;

mass of the doctor, m₁ = 75 kg

mass of the baby, m₂ = 4 kg

length of the doctor's arm, r = 0.3 m

universal gravitation constant, G = 6.67 x 10⁻¹¹ Nm²/kg²

The gravitational force F, is calculated as;

`F = (Gm_1m_2)/(r^2) \\\\F = ((6.67*10^(-11))(75 \ kg) (4 \ kg))/((0.3 \ m)^2) \\\\F = 2.223 *10^(-7) \ N`