Question

What is the volume of a hemisphere with a radius of 6.1 ft, rounded to the nearest

tenth of a cubic foot?

Answer 1

`V_(sm)=475.4\ ft^3`

Explanation:

Hemisphere

It's defined as half of a sphere. The volume of a sphere is:

`\displaystyle V_s=(4)/(3)\pi r^3`

Thus, the volume of a semisphere is half of that:

`\displaystyle V_(sm)=(2)/(3)\pi r^3`

We know the radius is r=6.1 ft, thus:

`\displaystyle V_(sm)=(2)/(3)\pi\cdot (6.1)^3`

`V_(sm)=475.38789\ ft^3`

Rounded to the nearest tenth:

`\boxed{V_(sm)=475.4\ ft^3}`