Question

Plz help fast there is a (pic)

Answer 1

`\boxed {s = 14}`

Explanation:

Solve for the value of
`s`:

`(2)/(3)s + (5)/(6)s = 21`

-Combine like terms:

`(2)/(3)s + (5)/(6)s = 21`

`(3)/(2)s = 21`

-Multiply
`(2)/(3)` on both sides, which is the reciprocal of
`(3)/(2)`, and multiply
`21` and
`2`:

`s = 21 * ((2)/(3))`

`s = (21 * 2)/(3)`

`s = (42)/(3)`

-Divide
`42` by
`3`:

`s = (42)/(3)`

`\boxed {s = 14}`

Therefore, the value of
`s` is
`14`.