16.8k views
0 votes
Plz help! How much heat is absorbed by a 3,000. g granite rock as energy from the

sun causes its temperature to change from 10.0°C to 29°C? Specific heat
capacity of granite is 0.79 J/g°C (Note: Make sure you use the lowest
significant figures in your answer. No need to write the units because you
will select it on the next question) *

User Kaspa
by
5.3k points

2 Answers

6 votes

Answer:

4

Step-by-step explanation:

Edge 2022

User Simeon Cheeseman
by
5.4k points
5 votes

Answer:

45,030 joules

Step-by-step explanation:

The specific heat capacity of granite is 0.79

Mass= 3000 g

Initial temperature= 10°C

Final temperature= 29°C

Therefore the quantity of heat can be calculated as follows

Quantity of heat= mass × specific heat capacity × (final temperature-initial temperature)

= 3,000 × 0.79 × (29-10)

= 3000 × 0.79 × 19

= 45,030 joules

Hence the quantity of heat is 45,030 joules

User Glen Little
by
5.6k points