Question

Find the coordinate of midpoint of seg given
(-2,2) and (6,4)

Answer 1

`\huge{ \fbox{ \sf{ \: ( \: 2 \:, 3 \: )}}}`

Explanation:

`\star{ \sf{ \: \: Let \: the \: points \: be \: A \: and \: B}} :`

`\star{ \sf{ \: Let \: A( - 2 \:, 2 \: ) \: be \: (x1 \:, y1) \: and \: B \: ( \: 6 \:, 4 \: ) \: be \: (x2 \:, y2)}}`

`\underline{ \sf{Finding \: the \: midpoint}} :`

`\boxed{ \sf{Midpoint = ( (x1 + x2)/(2) ,\: (y1 + y2)/(2) )}}`

`\mapsto{ \sf{Midpoint = ( ( - 2 + 6)/(2) \,, (2 + 4)/(2) }})`

`\underline{ \text{Remember!}}`

• The positive integers are always added and posses the positive ( + ) sign.
• The negative integers are always added but posses the negative ( - ) sign.
• The negative and positive integers are always subtracted but posses the sign of the bigger integer.

`\mapsto{ \sf{Midpoint = ( (4)/(2) ,\: (6)/(2) )}}`

`\mapsto{ \sf{Midpoint = ( \: 2 ,\: 3)}}`

Hope I helped!

Best regards! :D

~
`\text{TheAnimeGirl}`