Question

What is the number of moles of glucose (C,H,O,) in 0.500
of a 0.40
M
solution?

Answer 1

0.500

Step-by-step explanation:

We presume your "centroid ratio theorem" tells you that AG = 2·DG, so ...

(x+7) = 2(x -15)

x + 7 = 2x - 30 . . . . eliminate parentheses

37 = x . . . . . . . . . . .add 30-x

Then AG = 37+7 = 44

and DG = 37-15 = 22.

Of course, AD = AG +GD = 44 +22 = 66