Question

The perimeter of a rectangle is 48 feet, and the length is 16 feet. what is the area?

Answer 1

Answer:
`128ft^2`

Explanation:

If the 16ft is the sum for both sides already means the first length is 8ft and also the second length is 8ft. then since there are 32 ft more left, you divide it by two since there were two widths left, the values of the two widths are 16ft each. so the sum of the two widths is 32ft. and that's the final answer.

`Length=16`

`Perimeter=48`

`Using ~the ~formulas:`

`A=wl`

`P=2(l+w)`

`Solving ~for~A:`

`A=P(l)/(2) -l^2=48` ×
`(16)/(2) -16^2=128ft^2`

Answer 2

A= L•W
A= 16•8
A=128ft
The area of this rectangle is 128ft