Question

A student group at NAU collected information from a local dine in resturant indicating the tip amount left by customers over the course of a two year period. The tip amounts were roughly normally distributed with a mean of $7.84 and a standard deviation of $2.60

Answer 1

The desired range will be "($ 2.64, $ 13.04)".

Explanation:

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The given values are:

Mean

= $ 7.84

Standard deviation

= $ 2.60

Those are established by empirical rule whether 95% including its values cheat throughout two standard deviations of such the mean, for something like a roughly normal distribution results.

Thus, the range of values which might absorb 95% of all sums will be:

=
`(Mean - 2* Standard \deviation, Mean + 2* Standard \ deviation)`

On putting the estimated values, we get

=
`(7.84 - 2* 2.60, 7.84+ 2* 2.60)`

=
`(7.84-5.2, 7.84+5.2)`

=
`($2.64, $ 13.04)`