Question

One particle has a charge of 2.15 x 10^ -9 while another particle has a charge of 3.22 x 10^ -9 If the two particles are separated by 0.015 m, what is the electromagnetic force between them? A. 4.31 x 10^ -7 N B. 2.77 x 10^ -4 N C. 4.15 x 10^ -6 N D. 6.22 x 10^ -4 N

Answer 1

b

Step-by-step explanation:

a pex

Answer 2

B. 2.77 x
`10^(-4)` N

Step-by-step explanation:

The required force can be calculated by:

F =
`(Kq_(1)q_(2) )/(d^(2) )`

Where F is the force between the particles, K is the coulomb's constant (9 x
`10^(9)`
`Nm^(2)/C^(2)`),
`q_(1)` is the charge on the first particle,
`q_(2)` is the charge on the second particle and
`d^(2)` is the distance between the particles.

So that:

F =
`(9*10^(9)*2.15*10^(-9) *3.22*10^(-9) )/((0.015)^(2) )`

=
`(6.2307*10^(-8) )/((2.25*10^(-4) )`

= 2.7692 x
`10^(-4)`

The force between the particles is 2.77 x
`10^(-4)` N.