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Complete Question
Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an
hourly rate of $28. The plumber only charges for a whole number of hours. Anand would like to spend no more than $250, and he wonders how many hours of work he can afford.
Let H represent the whole number of hours that the plumber works.
1) Which inequality describes this scenario?
Choose 1 answer:
A. 28 + 65H < 250
B. 28 + 65H > 250
C. 65 + 28H < 250
D. 65 +28H > 250
2) What is the largest whole number of hours that Anand can afford?
Answer:
1) C. 65 + 28H < 250
2) 6 hours
Explanation:
We are told in the question that:
Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an
hourly rate of $28. The plumber only charges for a whole number of hours.
Hences we have:
$65 + 28 × H
We are told that:
Anand would like to spend no more than $250,
Hence,our equation becomes:
$65 + 28H ≤ $250
Where H = Hourly rates of the plumber.
1) Which inequality describes this scenario?
From the given options and our calculations above, Option C) 65 + 28H < 250 is the correct answer
2) What is the largest whole number of hours that Anand can afford?
We would use our equation above to solve for this.
65 + 28H < 250
= 65 + 28H ≤ 250
We convert or inequality sign to equal to sign
= 65 + 28H = 250
28H = 250 - 65
28H = 185
H = 185/28
H = 6.6071428571 hours
Therefore, the largest whole number of hours that Anand can afford is 6 hours