Question

You are studying a variety of pea plant that has either red flowers or white flowers. When you cross true-breeding red-flowering plants with true-breeding white-flowering plants, you get all red-flowering plants in the F1 generation. If you then allow the F1 plants to self-ferilize, you observe that 75% of the F2 plants are red-flowering plants, while 25% of the F2 plants are white-flowering plants. Next you make 640 different monohybrid crosses and decide to analyze only the first 8 plants produced from each of these crosses (i.e. a total of 5120 progeny plants total). How many of these crosses would be expected to produce 6 red plants and 2 white plants?

Answer 1

199 or 200

Step-by-step explanation:

The computation of the number of these crosses is shown below:

P (red) = 75% = a

P (white) = 25% = b

Now determine the probability of 6 red + 2 white and then multiplied it by 640

Now use the binomial theorem

now the required probability is

= 28 × (0.75)^6 × (0.25)^2 × 640

= 199.25

= 199 or 200

hence, the number of corsses is 200