Question

Hi, How would I go about solving this?

I got it wrong, so I must've missed something, I just don't know what.
My notes for rhombuses are: All sides are congruent. Diagonals are perpendicular. Diagonals are angle bisectors.

Answer 1

∠BAC = 122°

Explanation:

From your notes, you know that ...

∠APB = 90°

12y° = 90°

y = 90/12 = 7.5

Then angle ACP is ...

∠ACP = (4y -1)° = (4(7.5) -1)° = 29°

Angle BAC is the ape.x angle of isosceles triangle BAC, whose base angles are 29°. Hence, ...

∠BAC = 180° -2(29°)

∠BAC = 122°