Question

pooja needs 15 kg of water at 38 degree Celsius to take a bath, but her water is only at 20 degree Celsius. calculate the minimum amount of heat energy she requires to heat the water to the required temperature.​

Answer 1

Q = 1128.6 [kW] - kilowatts

Step-by-step explanation:

To calculate the amount of energy required, the following expression should be used:

`Q=m*c_(p)*(T_(f) - T_(i)) \\where:\\C_(p)=specific water heat = 4.18 [(kJ)/(kg*K)] \\m = mass = 15 [kg]\\T_(f)= Final temperature = 38 [C]\\T_(i)=20[C]`

Q = 15*4.18*(38-20)

Q = 1128.6 [kW]