Question

What number of moles of O2 is needed to produce 75 grams of P4010 from P?

(Molecular weight P40101 284 g/mol)

Answer 1

Step-by-step explanation:

We're using the chemical equation:

4P + 5O2 → P4O10

First convert grams of product to moles:

75g P4O10 x (1mol / 284 g) = 0.264 mol P4O10

Using the mole ratios, convert moles of product into moles of reactant needed:

0.264 mol P4O10 x (5 mol P / 1 mol P4O10) = 1.32 mol O2