Question

What is the percent error when a student measures the volume to be 19.3 liters when

the actual volume is 22.4 L.

Answer 1

The answer is

13.84 %

Step-by-step explanation:

The percentage error of a certain measurement can be found by using the formula

`P(\%) = (error)/(actual \: \: number) * 100\% \\`

From the question

actual volume = 22.4 L

error = 22.4 - 19.3 = 3.1

The percentage error is

`P(\%) = (3.1)/(22.4) * 100 \\ = 13.839285714...`

We have the final answer as

13.84 %

Hope this helps you