Question

A stadium has 49,000 seats. Seats sell for ​$25 in Section​ A, ​$20 in Section​ B, and ​$15 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in ​$1,053,500 from each​ sold-out event. How many seats does each section​ hold?

Answer 1

Explanation:

Suppose the number of seats in Section A is x, the number of seats in Section B is y, the number of seats in Section C is z.

1. The cost of all seats in Section A if each of it sells $25 is 25x.

The cost of all seats in Section B if each of it sells $20 is 20y.

The cost of all seats in Section C if each of it sells $15 is 15c.

Suppose the stadium takes in ​$1,053,500 from each​ sold-out event, so we have:

25x 20y 15c = 1,053,500 (1)

2. The number of seats in Section A equals the total number of seats in Sections B and C, so we have:

x = y z

x - y -z = 0 (2)

3. According to the prompt, a stadium has 49000 seats, so we have:

x y z = 49000 (3)

(1),(2), and (3) -> You have to solve the set of three equations.

Then we will have: x = 24500

y = 14700

z = 9800

Therefore, in section A, a stadium has 24500 seats.

in section B, a stadium has 14700 seats.

in section C, a stadium has 9800 seats.

Hope my answer can help you.