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Use Coulombs Law to calculate the force between a 0.05 C charge and a 0.06 C charge when they are 2 meters apart from each other

User Darrol
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1 Answer

3 votes

Answer:

6,740,663.84 N

Step-by-step explanation:

Coulombs Law states that
F = k(q_(1) q_(2))/(r^(2)), where k = coulombs law, q1 and q2 are charge one and charge 2 respectively, and r is distance

Substitute for q1 and q2, multiply .05 and .06 together


f= k (.003)/(r2)

Substitute for r, simplify
2^(2)


f= k (.003)/(4)

Divide .003 by 4


f=k*.00075\\

Substitute in k


f=(8.9875517873681764 * 109 N.m2.C-2)*.00075


force = 6740663.8405261

User Jkmacc
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