Question

Use Coulombs Law to calculate the force between a 0.05 C charge and a 0.06 C charge when they are 2 meters apart from each other

Answer 1

6,740,663.84 N

Step-by-step explanation:

Coulombs Law states that
`F = k(q_(1) q_(2))/(r^(2))`, where k = coulombs law, q1 and q2 are charge one and charge 2 respectively, and r is distance

Substitute for q1 and q2, multiply .05 and .06 together

`f= k (.003)/(r2)`

Substitute for r, simplify
`2^(2)`

`f= k (.003)/(4)`

Divide .003 by 4

`f=k*.00075\\`

Substitute in k

`f=(8.9875517873681764 * 109 N.m2.C-2)*.00075`

`force = 6740663.8405261`