Answer:
The statement is false for any value of y.
Explanation:
3(4y+6) ≤ −2(3−6y)
Step 1: Distribute
12y + 18 ≤ -6 + 12y
Step 2: Cancel out equal terms on both sides
12y + 18 ≤ -6 + 12y
-12y -12y
18 ≤ -6
There is no more y variable.
Therefore the statement is false for any value of y.