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Solve 3(4y+6) ≤ −2(3−6y)

2 Answers

1 vote

Answer:

The statement is false for any value of y.

Explanation:

3(4y+6) ≤ −2(3−6y)

Step 1: Distribute

12y + 18 ≤ -6 + 12y

Step 2: Cancel out equal terms on both sides

12y + 18 ≤ -6 + 12y

-12y -12y

18 ≤ -6

There is no more y variable.

Therefore the statement is false for any value of y.

User Brian Salta
by
4.6k points
2 votes

Answer:

0 ≤ -24 ( can't be true)

Explanation:

3(4y+6) ≤ -2(3-6y)

12y + 18 ≤ -6 + 12y

0 ≤ -24

not true ( can't be true)

User John Fish
by
4.3k points