Question

Find value of X in the given right triangle.

Answer 1

7.1

Explanation:

you use the Pythagorean theorem to solve this problem. a^2+b^2=c^2.

you are finding value of b plug the variables in = 7^2+b^2=10^2

=49+b^2=100

subtract 49 from both sides

b^2=51

Square root of 51 =7.141 round to nearest tenth =7.1

Answer 2

44.4

Explanation:

it is a right angled triangle so

with reference angle x

perpendicular (p) = 7

hypotenuse (h) = 10

so Now

sin x = p/h

sin x = 7 / 10

x = sin^-1( 7/ 10)

x = 44.42°

Rounding to nearest tenth

= 44.4°