Answer:
If in volume of 10.0L it is 25°C than it will be 37.5C volume in the new temperature if increased from 10.0L to 15.0L
Step-by-step explanation:
10.0L=25°C
15.0L=?
10×2.5= 25
15×2.5=37.5
Kelvin(K)= C+273=T
=37.5+275=312.5
=C=312.5-275
=C=37.5
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