Question

(a) Which of the following atoms is smallest: vanadium, chromium or tungsten? (b) Which of these atoms has the highest ionization energy? (c) Which is the most electronegative?

Answer 1

Chromium is the smallest atom, tungsten has the highest ionization energy, and oxygen is the most electronegative atom.

Step-by-step explanation:

(a) The smallest atom in this group is chromium because it has the least number of electrons and protons among the given options. As you move across a period from left to right, the atomic size decreases due to the increase in effective nuclear charge.

(b) The atom with the highest ionization energy is tungsten because it requires the most energy to remove an electron from its outer shell. Ionization energy generally increases as you move across a period from left to right.

(c) The most electronegative atom among the given options is oxygen (not provided in the given options). Oxygen has a higher electronegativity because it has a greater tendency to attract electrons towards itself when bonding.

Answer 2

Answer: (a) chromium (b) tungsten (c) tungsten

Step-by-step explanation:

As we move towards the right in the periodic table, atomic sizes decreases and electronegativity increases accordingly. Similarly, atomic sizes increases down the group. Hence chromium is smaller than tungsten.

However, tungsten is more electronegative than the other metals listed, as a result of this, it also has the highest first ionization energy. Hence the answer above.