Question

What is the factorization of 1,000x^6-27

Answer 1

Cube root 1000x^6 = 10x^2

Cube root of - 27 = 3

So the first part of the factorization process is 10x^2 - 3. There is no help here because all of the answers give this binomial as the first factor.

The second factor is (10x^2)^2 + (3)*10x^2 + 3^2)

Expanding you get 100x^4 + 30x^2 + 9

100x^4