Solve for K given that {125}^(k + 1) + {5}^(3k) = 630

asked Aug 11, 2021 58.5k views

1 vote

Solve for K given that

${125}^(k + 1) + {5}^(3k) = 630$

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2 votes

Answer:

k = 1/3

Explanation:

$Solve for K given that {125}^(k + 1) + {5}^(3k) = 630 -example-1$

Carewithl answered Aug 16, 2021

5.2k points

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