Question

How much energy is required to heat 108.1g H2O (molar mass = 18.01) from a liquid at 65°C to a gas at 115°C?

Answer 1

The energy is 22.592 kJ.

Step-by-step explanation:

Given that,

Mass of
`H_(2)O` = 108.1 g

Molar mass = 18.01

Initial temperature = 65°C

Final temperature = 115°C

We need to calculate the energy

Using formula of energy

`Q_(1)=mc\Delta T`

Put the value into the formula

`Q_(1)=108.1*4.18(115-65)`

`Q_(1)=22592.9\ J`

`Q_(1)=22.592\ kJ`

Hence, The energy is 22.592 kJ.