Question

How many grams is 3.89 x 10^28 atoms of Sulfur?

Answer 1

`M=2.06* 10^6\ g`

Step-by-step explanation:

In this problem, we need to find how many grams is 3.89 x 10²⁸ atoms of Sulfur.

It can be calculated using below formula :

`\text{No of atoms}=\frac{\text{Mass}}{\text{Molar Mass}}* \text{Avagadro's number}\\\\\text{Mass}=\frac{\text{No. of atoms}* \text{Molar mass}}{\text{Avagadro's number}}\\\\\text{Mass}=(3.89* 10^(28)* 32)/(6.022* 10^(23))\\\\\text{Mass}=2067087.34\ g\\\\\text{or}\\\\M=2.06* 10^6\ g`

So, the mass of Sulfur is
`2.06* 10^6\ g`.