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how many moles of nitrogen gas will occupy a volume of 0.347 l at 7.0 atm and 300 k?
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User Amr Hossam
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1 Answer

8 votes

Answer:

.0987 moles

Step-by-step explanation:

Ideal gas law PV = n RT R = .082057 L-atm/mol-K

7 ( .347) = n (.082057) (300) n = .0987 moles

User Dpapadopoulos
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